Position of Hydrogen in the Reactivity Series of Metals
Reactivity Series
K, Na, Ca, Mg, Al, C, Zn, H, Fe, Sn, Pb, Cu, Hg, Ag, Au
<——– increase in reactivity
Metal oxide + Hydrogen –> Metal + Water
Any metal below hydrogen in the reactivity series, hydrogen will reduce the oxide of metal to metal.
Example 1:
- CuO(s) + H2(g) –> Cu(s) + H2O(l)
- Observation: Burns quickly with a bright flame. The black solid turns brown solid.
- H2: Reducing agent
- CuO: Oxidising agent
- Hydrogen is more reactive than copper.
- PbO(s) + H2(g) –> Pb(s) + H2O(l)
- Observation: Burns with a bright flame. The yellow solid turns grey solid.
- H2: Reducing agent
- PbO: Oxidising agent
- Hydrogen is more reactive than lead.
- Fe2O3(s) + 3H2(g) –> 2Fe(s) + 3H2O(l)
- Observation: Glows dimly. The reddish-brown solid turns grey solid.
- H2: Reducing agent
- Fe2O3: Oxidising agent
- Hydrogen is more reactive than iron.
- ZnO(s) + H2(g) –> no reaction
- Observation: No glow is observed. It turns yellow when hot and white when cold.
- Hydrogen is unable to reduce zinc oxide. Hydrogen is less reactive than zinc.
Similarities
- redox reaction.
- Anode: oxidation
- Cathode: reduction
- Electrons flow from anode to cathode in the external circuit
Differences | Electrolytic Cell (Electrolysis) | Chemical Cell / Voltaic Cell |
Structure | With electrical supply. | No electrical supply. |
Electrodes | Can be the same or difference metal (graphite or platinum). | Must be two different metals. |
Flows of electrons | From anode to cathode through external circuit. | From more electropositive metal to less electropositive metal through external circuit. |
Transformation of energy | Electrical energy to chemical energy. | Chemical energy to electrical energy. |
At positive terminal | Anode.Oxidation occurs. Anions release electrons at the anode. | Cathode.Reduction occurs. Oxidising agent gain electrons. |
At negative terminal | Cathode.Reduction occurs. Cations gain electrons from the cathode. | Anode.Oxidation occurs. Reducing agent releases electrons. |
Example 1: Electrolysis of molten zinc chloride
- Electrodes: Carbon
- Ions present: Cl- and Zn2+
- Anode: Oxidation / 2Cl-(l) –> Cl2(g) + 2e / Cl- ions act as reducing agent.
- Cathode: Reduction / Zn2+(l) + 2e –> Zn(s) / Zn2+ ions act as oxidising agent.
- Electrodes: Carbon
- Ions present: Cu2+, SO42-, H+, OH-
- OH- ions are discharged because OH- ion is below SO42- ion in electrochemistry series.
Anode: Oxidation / 4OH-(aq) –> O2(g) + 2H2O(l) + 4e / Oxygen gas is liberated. - Cu2+ ions are discharged because Cu2+ ion is below H+ ion in electrochemistry series.
Cathode: Reduction / Cu2+(aq) + 2e –> Cu(s) / Cu2+ ions are reduced to copper metal (brown layer formed). - –> Overall equation: Cu2+(aq) + 4OH-(aq) –> O2(g) + 2H2O(l) + Cu(s)
- Electrodes: Copper
- Ions present: Cu2+, SO42-, H+, OH-
- OH- ions and SO42- ion are not discharged.
Anode: Oxidation / Cu(s) –> Cu2+(aq) + 2e / Copper anode (electrode) dissolves. - Cu2+ ions are discharged because Cu2+ ion is below H+ ion in electrochemistry series.
Cathode: Reduction / Cu2+(aq) + 2e –> Cu(s) / Cu2+ ions are reduced to copper metal.
- Electrodes: Carbon
- Ions present: Na+, Cl-, H+, OH-
- Cl- ions are discharged because of the higher concentration. (Concentration of Cl- ion is high, the ion is selectively discharged rather than the OH- ion, the one that is placed below the electrochemical series.)
Anode: Oxidation / 2Cl-(aq) –> Cl2(g) + 2e / Chlorine gas (green gas with choking smell) is liberated. - H+ ions are discharged because Na+ ion is below H+ ion in electrochemistry series. (H+ ions and Na+ ion are placed very far apart in the electrochemical series, the concentration factor becomes unimportant.)
Cathode: Reduction / 2H+(aq) + 2e –> H2(g) / Hydrogen gas is liberated. - –> Overall equation: 2Cl-(aq) + 2H+(aq) –> Cl2(g) + H2(g)
Example 1: Daniel cell
- Anode (negative terminal): Oxidation / Zinc strip immerses in zinc sulphate solution.
Zn(s) –> Zn2+(aq) + 2e / Zinc strip becomes thinner. - Cathode (positive terminal): Reduction / Copper strip immerses in copper(II) sulphate solution.
Cu2+(aq) + 2e –> Cu(s) / A brown layer formed around copper strip. / Concentration Cu2+ ions decreases cause the intensity blue colour of solution decreases. - Zinc is more electropositive than copper. Electrons are flowed from zinc strip to copper strip through the external circuit. (Note: Conventionally, electrons flow in the opposite direction of electrical current).
- –> Overall equation: Zn(s) + Cu2+(aq) –> Zn2+(aq) + Cu(s)